Sunday, April 17, 2011
Friday 4/15/11
Thursday, April 14, 2011
Thurs 4/14/11
Wednesday, April 13, 2011
Friday, 4/8/11, Acids and Bases
Acids and Bases, 4/8/11
1. Went over the properties of acids and bases.
2. Took a partner quiz on acids and bases.
3. Took notes.
NOTES:
Part 1- The Simulation
1. List the molecules and/or ions present in the solution of HCl.
-H+ Cl- H20
2.List the molecules and/or ions present in the solution of NaOH.
-Na+ OH- H2O
3. What is the purpose of the phenolphthalein (phth)?
-it is an indicator (base/ OH- turns pink)
4. Why doesnt the phenolphthalein change colors when it is first added to the cup?
-Acid + pht
NO OH-
5. What is the reaction that is happening when the NaOH is added to the cup?
-Neutralization reaction, NaOH + HCl produces NaCl + H2O
6. What has to be true for the phenolphthalein to turn pink?
- OH- > H+
first slight pink
EQUIVALENCE POINT
4. Part 2 of the notes: We did a lab using the base NaOH and the acid HCl. In the lab we had to put 10drops of HCl into a paper cup with one drop of phth. Next we add 1 drop of NaOH into the cup and mix it around when we see the pink. We continued this procedure until the pink remained the color of the mixture. Here is my groups data:
Drops HCl (.40M) Drops NaOH (X M)
Trial 1 10 36
Trial 2 10 31
Trial 3 10 67
Trial 4 10 63
We then used the equation Macid x Drops acid = Mbase x Drops base to figure out the molarity of NaOH in each trial. Here are our results:
Trial 1- .11 Trial 2- .13
Trial 3- .06 Trial 4- .06
The average concentration of the NaOH was .18.
In our lab results we had deviant trials. You can disguard deviant trials however mention it.
Posted by Therese Snow at 8:21 PM 0 comments
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Labels: Acids and Bases, Snow
Tuesday, April 12, 2011
Acids and Bases
Monday, April 11, 2011
Solubitity
Thursday, April 7, 2011
Thursday, April 7th 2011- Emma N.
Thursday, March 24, 2011
Thursday, March 24th 2011- Emma N.
Wednesday, March 23, 2011
Tue, 3/22,Eman
CALCULATIONS
1. Mass of original water
101.66 g.
2. Mass of water from melted ice (subtract mass of ice in water from the original water)
17.71 g.
3. Change in temperature of water
13 degrees Celsius
4. Amount of heat lost by original
5,524.2 J.
5. Heat Fusion for the Ice
311.914 J/g
QUESTIONS
1.Is the process of the ice melting endothermic or exothermic?
Endothermic. Heat is traveling on/into the ice.
2.Is the process of the ice freezing endothermic or exothermic?
Exothermic. The energy is traveling out of the ice.
SKIP #3
We then continued on to the worksheets we had picked up in class. We had done #1 a & b in class. These are the answers we got as a class for that sheet:
1. CH4 + 2o2 -> CO2 +2H2O
a. 4.00 g of Methane (CH4) is allowed to burn according to the reaction above. The energy released by the reaction is used to head 800 grams of water from 15.0 degrees Celsius to 81 degrees Celsius.
-Find the energy released by the reaction in kJ.
800g x 4.18J/gºC x 66.4ºC = (app.) 222 kJ
-Find the moles of CH4 burned.
4.0g CH4 x 1mol/16.04g = .249 mol CH4
-Find Delta H in kJ/mol (including the sign) for the reaction above.
222kJ/.249 mols = 892 kj/mols
** remember delta H (which is heat associated with reaction)/ 892 kj/mol
b. In another experiment 1.55 g of CH4 is burned. How much energy would be released?
1.55 g CH4 x 1 mol CH4/16.04 g CH4 x 892 kJ/1 mol CH4 = 86.197 KJ -> 86.2 kJ
By the time we had gone over these problems in class, we were instructed to finish the rest of the two sheets for homework!
Monday, March 21, 2011
Michelle - Monday March, 21
Finally we conducted the Heat of Fusions Lab. The procedure to conduct the lab can be found on the journal page he handed to us in class. It looks like this.
Sunday, March 20, 2011
Andrew- Friday, March 18th, Chem Day
Today for class we went to the auditorium to watch Mythbusters for a chem day. The Mythbusters episode was called "Crime & Mythdemeaners" and had to do with different security systems. We had to fill out a sheet with 30 questions having to do with the video.
The first part of the episode had to do with a fingerprint lock. They tried different methods of copying a fingerprint in order to trick the fingerprint lock. One of the questions we had to answer was:
What material was most like human skin?
Ballistic Gel
Ballistic gel was used to make a fingerprint very similar to a human fingerprint so they could fool the sensor on the door.
The second part of the mythbusters episode had to do with thermal motion alarms. Thermal motion alarms take an average room temperature reading, and are set off when the temperature is changed by the presence of a person.
The third part of the mythbusters episode tested out an ultrasonic motion detector. The motion detector is set off when someone walks past it. The mythbusters thought that if the person is undetectable than the alarm would not go off. They tested this theory by having someone walk through the room with a big white sheet over them, and the alarm did not go off.
In the final part of the mythbusters episode the final myth had to do with filling up a safe with water than dropping an explosive with nitroglycerin into it making the door fly off with a huge explosion. This myth came from a movie where this was done, and the villain got away with the goods inside. After numerous failed attempts the mythbusters finally got everything to work our just how they wanted. At the end they finally dropped the explosive into the water like the movie, and a huge explosion made the door go flying. Everything on the inside of the safe was destroyed though so the movie was not too realistic.
Thursday, March 17, 2011
Thursday, March 17th ( St. Patrick's Day)
Here are the notes:
1. Temperature-
Average kinetic energy of the particles in a substance.
Units Used: Fahrenheit( we don't use this in class), Celsius and Kalvin.
2. Heat-
Transfer of Energy (joules).........Can be gained or lost.
Tuckers Joke: " There's also dominicks and walgreens".....yaaaa? no comment
3. Heat loss and Gain
Endothermic- Gaining heat
Exothermic- Loosing Heat.
In between notes we did a quick observation of Mr Tuckers " Magic Blocks." One block was wood and one was metal. The wood block was warm, compared to the metal block. After putting a piece of ice on both blocks, the ice melted faster on the metal block!! This was all due to the energy transfer.
Graph on page 2 of notes ( at top of blog):
Part1.A Heating and Cooling of a solid
Heat (q)= M * Cp ΔT (Tf-Ti)
Part2B Melting solid <-> Liquid freezing
Heat= M * HF
Part3C Heating/Cooling a Solid
Heat (q)= M * Cp ΔT (Tf-Ti)
Part 4D Boil a liquid <-> Gas condenses
Heat= M * HV ( Heat Vaporization )
Part5E Heating/Cooling a Gas
Heat (q)= M * Cp ΔT (Tf-Ti)
Wednesday, March 16, 2011
Wednesday 3/16/2011
Friday, March 11, 2011
Fri, Kin./EQ Review / Tucker
if reaction shifts left, then NO2 and O2 increase and NO3 decreases on the graph
the opposite of decrease temp in INCREASE TEMP so shift left towards the heat
Decrease H2- shift left
Add a catalyst…… skip, do not worry
Increase volume…..skip, do not worry
a) True, if K is greater than 1 the products are favored (K = P/R)
15. First, find the concentrations of all substances by dividing mols by 5L
Thu, Kin./EQ Practice / Tucker
From top left to right
1. 2.22
2. 125
3. 8
4. 1.17E-5
5. 1.33
6. 0.942
7. 10
8. 0.868
9. 7.13E-5
a) about 98.6F, Homeostasis…like hair and shivering
b) about 98.6F, Homeostasis, like sweating
c) Yes, body keeps changing in response to external conditions
d) House heats up, thermostat increases, air conditioner turns on, House cools down, Thermostat decreases, air conditioner turns off
e) Body changes OPPOSITELY in response to stresses(changes) on it…it tries to fix itself.
a) Temp, Time
b) Amounts of A and B
c) about 1-2seconds
d) Inverse, as T goes up, time goes down
e) Cannot predict, A may not react with C
1.
a. K= [P] / [R]
b. K = [NO2]2 x [Br2] / [NOBr]2c) NOBr- 109.9g/mol, NO- 30g/mol, Br2- 159.9g/mol
d) NOBr- 0.910 mol, NO- 0.333 mol, Br2- 0.625 mol
e) 5L
f) mol / L
g) NOBr- 0.182M, NO- 0.0667M, Br2- 0.0125M
h) K= 0.00168
a) double arrow
b) forward reaction = reverse reaction, concentrations of reactants and products are constant
c) +, reactant side…….do not worry, I will always tell you what side the heat is on for now
d) 2mols reactant, 3 mols product
e) More, Less
f) GIVEN
g) add SO2, right, SO2 and O2, SO3, more moles gas, increase
h) decrease O2, left, SO3, SO2 and O2, less moles gas, decrease
i) decrease temp, right, SO2 and O2, SO3, more moles gas, increase
j) increase pressure, right, SO2 and O2, SO3, more moles gas, increase
Thursday, March 3, 2011
Thu, 3/3, Tucker
WE JUST WROTE THIS LAB IN OUR JOURNALS!!
Lab 1:
Procedure: Place 1/4 alka seltzer tablets in 25ml of water in a 50ml flask and place a balloon over the top of the flask. Time how long it takes for the balloon to inflate. Repeat with 1/2 and full tablets.
Data:
1/4tablet- 45sec
1/2 tablet- 14sec
1 tablet- 6sec
Conclusion: As concentration increases, so does the speed of the reaction
Lab 2:
Preocedure: Place 1/2 alka seltzer in in 25ml of water in a 50ml flask and place a balloon over the top of the flask. Time how long it takes for the balloon to inflate. Repeat with a crushed alka-seltzer (which has more surface area!)
Data:
1/2 tablet - 16sec
1/2 tablet crushed- 5sec
Conclusion: As surface area increases, so does the speed of the reaction
Lab 3:
Procedure: Place 1/2 tablet of alka-seltzer in 25ml of room temperature water (22 degreesC) in a 50ml flask and place a balloon over the top of the flask. Time how long it takes for the balloon to inflate. Repeat this with 5degreesC water and 50 degreesC water.
Data:
5C- 2min, 20sec
22C- 20sec
50C- 4sec
Conclusion: As temperature increases, so does the speed of the reaction
The independent variables for the lab were concentration, surface area, and temperature
The dependent varibale for the lab was time / speed of the reaction
The controlled varibales for the lab were the size of flask, type of tablets, and amount of water.
Wednesday, February 23, 2011
Kyle-Wednesday, 2/23 Solubitity
- NaNO3(aq) + AgNO3(aq) ------> NaNO3(aq) + AqNO3(aq)
- Their is no reaction because all four coumpounds are soluble in water(aq).
- You just put a line through the problem or say NR.
| MgCl2 | K3PO4 | NaNO3 | Na2CO3 | AgNO3 | CuSO4 |
MgCl2 | X | X | X | X | X | X |
K3PO4 | Rxn-Cloudy color | X | X | X | X | X |
NaNO3 | NR | NR | X | X | X | X |
Na2CO3 | Rxn-Cloudy color | NR | NR | X | X | X |
AgNO3 | Rxn-Cloudy color | Rxn-turned yellow | NR | Rxn-Cloudy color | X | X |
CuSO4 | NR | Rxn-Cloudy color | NR | Rxn-Cloudy color | NR | X |
Here are some examples of a reaction taking place. Make sure to use the Solubility Rules worksheet as a cheat cheat. Notice how one product is a solid(s) and the other is aqueous(aq).
- K3PO4(aq) + 3MgCl2(aq) ------> 6KCl(aq) + Mg3(PO4)2(s)
- Na2CO3(aq) + MgCl2(aq) ------> 2NaCl(aq) + MgCO3(s)
- 2AgNO3(aq) + MgCl2(aq) -------> 2AgCl(s) + Mg(NO3)2(aq)
- 3AgNO3(aq) + K3PO4(aq) -------> Ag3PO4(s) + KNO3(aq)
- 3CuSO4(aq) + K3PO4(aq) -------> Cu3PO4(s) + 3KSO4(aq)
- 2NaNO3(aq) + MgCl2(aq) -----> 2NaCl(aq) + Mg(NO3)2(aq)
- AgNo3(aq) + NaNO3(aq) -------> AgNO3(aq) + NaNO3(aq)
Tuesday, February 22, 2011
Natalie- Tuesday, 2/22
- Molarity= unit of concentration
- Use formula to determine how many mols of solute needed to make 0.15 M of solution
- If you need help with the formula use this video as a reference: http://www.youtube.com/watch?v=8oTqwBAvbnY&feature=fvwrel
.015 mol NaCl
58.44g NaCl
1 mol NaCl
- Fill beaker with 50 mL of water
- Then mix in .88g of Solute (NaCl)
- Then fill rest of the beaker to 100 mL
- Soluble in water= dissolves in water (aqueous)
- In soluble= does not dissolve in water (solid)
- There are some exceptions though, mentioned on the sheet
- If the balanced equation has aqueous on both sides, then no reaction has taken place
Monday, February 21, 2011
Shayne - Friday, 2/18
II. We went through the Molarity 2 notes:
EXAMPLES:
1.) What will be actually present in the solution when each of the following is added to water?
a. KCL ----------> K+ (aq) plus Cl- (aq)
b. NaNO3 ----------> Na+ (aq) plus NO3- (aq)
c. C2H6O ----------> C2H6O (aq)
3.) Calculate the mlarity (M) of the following solutions. (M = Mol/L)
a. M = 0.0346 Mols/0.250 Liters = 0.138M
b. (405 g NiCl2 X 1 mol NiCl2)/129.59 g NiCl2 = 3.12524 mols NiCl2
M = 3.12524 Mols/7.54 Liters = 0.414M
c. (22.57 g H2SO4 X 1 mol H2SO4)/98.09 g H2SO4 = 0.23009 mols H2SO4
100 Ml = 0.1 L so.....
M = 0.23009 Mols/0.1 L = 2.301M
5.) Calculate the mass of the solute present in the following solutions.
a. Mol = M x L so...
0.125M x 0.200L = (0.25 Mols Kbr x 119 g KBr)/1 Mol KBr = 2.98 g KBr
b. Mol = M x L so...
Mol = 0.150M x 0.1L
(0.015 Mols Na2SO4 x 126.05 g Na2SO4)/1 mol Na2SO4 = 1.89 g Na2SO4
III. We took a lab test in groups of two, having to make a solution of 0.15M of NaCl and show calculations
Thursday, February 17, 2011
Th-2/17-Gabuzzi
1. We picked up 2 sheets.
- Molarity 1
- Dissolving 1
2. We took a quiz on the mixtures notes we took on wednesday.
3. We then review the different types of substances and mixtures.
4. We finished the Solution Notes
III. Solutions . (we used salt water as an example)
A. Solute- dissolved (salt)
B. Solvent- doing dissolving (water)
C. Solution- solute and solvent (mixture of salt water)
D. Concentration of solution:
M=molarity
M= 1 mol solute per liter of solution. 1.0m=1 moler.
E. Preparation of solution:
- find total volume
- fill container 1/2 way with solvent
- add a solute and mix
- fill container to desired volume with solvent
We filled out the Molarity 1 and Dissolving 1 Worksheets (see photos at top for answers)
Homework: Finish Molarity 1 worksheet or we will be doing webassigns for the rest of the year.